1.6x^2-3.2x+1.6=x^2

Solution for 1.6x^2-3.2x+1.6=x^2 equation:

1.6x^2-3.2x+1.6=x^2

We move all terms to the left:

1.6x^2-3.2x+1.6-(x^2)=0

determiningTheFunctionDomain
1.6x^2-x^2-3.2x+1.6=0

We add all the numbers together, and all the variables

0.6x^2-3.2x+1.6=0

a = 0.6; b = -3.2; c = +1.6;
Δ = b2-4ac
Δ = -3.22-4·0.6·1.6
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{6.4}}{2*0.6}=\frac{3.2-\sqrt{6.4}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{6.4}}{2*0.6}=\frac{3.2+\sqrt{6.4}}{1.2}
$